0=-16t^2+37t-21

Solution for 0=-16t^2+37t-21 equation:

0=-16t^2+37t-21

We move all terms to the left:

0-(-16t^2+37t-21)=0

We add all the numbers together, and all the variables

-(-16t^2+37t-21)=0

We get rid of parentheses

16t^2-37t+21=0

a = 16; b = -37; c = +21;
Δ = b2-4ac
Δ = -372-4·16·21
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-5}{2*16}=\frac{32}{32}
=1
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+5}{2*16}=\frac{42}{32}
=1+5/16
$